Search a number
-
+
132689188117 is a prime number
BaseRepresentation
bin111101110010011100…
…1000101010100010101
3110200111100010011012201
41323210321011110111
54133221413004432
6140542341444501
712405106326643
oct1734471052425
9420440104181
10132689188117
1151300650a52
1221871410731
13c688073cc5
1465ca6c6193
1536b8eaeee7
hex1ee4e45515

132689188117 has 2 divisors, whose sum is σ = 132689188118. Its totient is φ = 132689188116.

The previous prime is 132689188057. The next prime is 132689188123. The reversal of 132689188117 is 711881986231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72749417841 + 59939770276 = 269721^2 + 244826^2 .

It is a cyclic number.

It is not a de Polignac number, because 132689188117 - 227 = 132554970389 is a prime.

It is a super-2 number, since 2×1326891881172 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132689188147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66344594058 + 66344594059.

It is an arithmetic number, because the mean of its divisors is an integer number (66344594059).

Almost surely, 2132689188117 is an apocalyptic number.

It is an amenable number.

132689188117 is a deficient number, since it is larger than the sum of its proper divisors (1).

132689188117 is an equidigital number, since it uses as much as digits as its factorization.

132689188117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1161216, while the sum is 55.

The spelling of 132689188117 in words is "one hundred thirty-two billion, six hundred eighty-nine million, one hundred eighty-eight thousand, one hundred seventeen".