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132701064173 is a prime number
BaseRepresentation
bin111101110010110011…
…0011000101111101101
3110200112011110112002122
41323211212120233231
54133232433023143
6140543444202325
712405312302006
oct1734546305755
9420464415078
10132701064173
1151307322677
12218753993a5
13c68a671762
1465cc0d81ad
1536ba058c68
hex1ee5998bed

132701064173 has 2 divisors, whose sum is σ = 132701064174. Its totient is φ = 132701064172.

The previous prime is 132701064131. The next prime is 132701064187. The reversal of 132701064173 is 371460107231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88145453449 + 44555610724 = 296893^2 + 211082^2 .

It is a cyclic number.

It is not a de Polignac number, because 132701064173 - 210 = 132701063149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132701064113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66350532086 + 66350532087.

It is an arithmetic number, because the mean of its divisors is an integer number (66350532087).

Almost surely, 2132701064173 is an apocalyptic number.

It is an amenable number.

132701064173 is a deficient number, since it is larger than the sum of its proper divisors (1).

132701064173 is an equidigital number, since it uses as much as digits as its factorization.

132701064173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21168, while the sum is 35.

The spelling of 132701064173 in words is "one hundred thirty-two billion, seven hundred one million, sixty-four thousand, one hundred seventy-three".