Base | Representation |
---|---|
bin | 10011010011111000010… |
… | …010011010000011100011 |
3 | 11200212020222210011002012 |
4 | 103103320102122003203 |
5 | 133220211432031201 |
6 | 2453342243343135 |
7 | 164605452441131 |
oct | 23237022320343 |
9 | 4625228704065 |
10 | 1327015502051 |
11 | 471869723798 |
12 | 195226981aab |
13 | 981a2075005 |
14 | 483294a4751 |
15 | 247baa1d5bb |
hex | 134f849a0e3 |
1327015502051 has 2 divisors, whose sum is σ = 1327015502052. Its totient is φ = 1327015502050.
The previous prime is 1327015502027. The next prime is 1327015502107. The reversal of 1327015502051 is 1502055107231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1327015502051 - 234 = 1309835632867 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 1327015501999 and 1327015502017.
It is not a weakly prime, because it can be changed into another prime (1327015502251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 663507751025 + 663507751026.
It is an arithmetic number, because the mean of its divisors is an integer number (663507751026).
Almost surely, 21327015502051 is an apocalyptic number.
1327015502051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1327015502051 is an equidigital number, since it uses as much as digits as its factorization.
1327015502051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10500, while the sum is 32.
The spelling of 1327015502051 in words is "one trillion, three hundred twenty-seven billion, fifteen million, five hundred two thousand, fifty-one".
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