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1327032987233 is a prime number
BaseRepresentation
bin10011010011111001010…
…101000110111001100001
311200212022012200111020112
4103103321111012321201
5133220230421042413
62453344110221105
7164606054164262
oct23237125067141
94625265614215
101327032987233
11471878586658
121952307b4795
13981a5887885
144832b936969
15247bc3242a8
hex134f9546e61

1327032987233 has 2 divisors, whose sum is σ = 1327032987234. Its totient is φ = 1327032987232.

The previous prime is 1327032987179. The next prime is 1327032987283. The reversal of 1327032987233 is 3327892307231.

It is an a-pointer prime, because the next prime (1327032987283) can be obtained adding 1327032987233 to its sum of digits (50).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1276161086929 + 50871900304 = 1129673^2 + 225548^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1327032987233 is a prime.

It is a super-2 number, since 2×13270329872332 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1327032987283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 663516493616 + 663516493617.

It is an arithmetic number, because the mean of its divisors is an integer number (663516493617).

Almost surely, 21327032987233 is an apocalyptic number.

It is an amenable number.

1327032987233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1327032987233 is an equidigital number, since it uses as much as digits as its factorization.

1327032987233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2286144, while the sum is 50.

The spelling of 1327032987233 in words is "one trillion, three hundred twenty-seven billion, thirty-two million, nine hundred eighty-seven thousand, two hundred thirty-three".