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13270710836507 is a prime number
BaseRepresentation
bin1100000100011101010000…
…0000010101110100011011
31201222200000122200220000112
43001013110000111310123
53214411403433232012
644120251433154535
72536530404631605
oct301072400256433
951880018626015
1013270710836507
114257093333a53
1215a3b5225ba4b
13753565786847
1433c43d2b8175
15180305830122
hexc11d4015d1b

13270710836507 has 2 divisors, whose sum is σ = 13270710836508. Its totient is φ = 13270710836506.

The previous prime is 13270710836431. The next prime is 13270710836557. The reversal of 13270710836507 is 70563801707231.

It is an a-pointer prime, because the next prime (13270710836557) can be obtained adding 13270710836507 to its sum of digits (50).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13270710836507 - 216 = 13270710770971 is a prime.

It is a super-2 number, since 2×132707108365072 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13270710836557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6635355418253 + 6635355418254.

It is an arithmetic number, because the mean of its divisors is an integer number (6635355418254).

Almost surely, 213270710836507 is an apocalyptic number.

13270710836507 is a deficient number, since it is larger than the sum of its proper divisors (1).

13270710836507 is an equidigital number, since it uses as much as digits as its factorization.

13270710836507 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1481760, while the sum is 50.

The spelling of 13270710836507 in words is "thirteen trillion, two hundred seventy billion, seven hundred ten million, eight hundred thirty-six thousand, five hundred seven".