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1327106624287 is a prime number
BaseRepresentation
bin10011010011111101101…
…110000000101100011111
311200212111100020122021211
4103103331232000230133
5133220403243434122
62453355300405251
7164610640116463
oct23237556005437
94625440218254
101327106624287
11471906101224
121952513a6827
13981b7bca9b2
14483376244a3
15247c3a1c877
hex134fdb80b1f

1327106624287 has 2 divisors, whose sum is σ = 1327106624288. Its totient is φ = 1327106624286.

The previous prime is 1327106624227. The next prime is 1327106624321. The reversal of 1327106624287 is 7824266017231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1327106624287 is a prime.

It is a super-2 number, since 2×13271066242872 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1327106624287.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1327106624227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 663553312143 + 663553312144.

It is an arithmetic number, because the mean of its divisors is an integer number (663553312144).

Almost surely, 21327106624287 is an apocalyptic number.

1327106624287 is a deficient number, since it is larger than the sum of its proper divisors (1).

1327106624287 is an equidigital number, since it uses as much as digits as its factorization.

1327106624287 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1354752, while the sum is 49.

The spelling of 1327106624287 in words is "one trillion, three hundred twenty-seven billion, one hundred six million, six hundred twenty-four thousand, two hundred eighty-seven".