Base | Representation |
---|---|
bin | 10011010100000110010… |
… | …101001011111001000011 |
3 | 11200212212102010100110202 |
4 | 103110012111023321003 |
5 | 133221202241031431 |
6 | 2453421501315415 |
7 | 164614343206124 |
oct | 23240625137103 |
9 | 4625772110422 |
10 | 1327251111491 |
11 | 47197a718638 |
12 | 195291865b6b |
13 | 9820bb19596 |
14 | 4834c8b604b |
15 | 247d155d8cb |
hex | 1350654be43 |
1327251111491 has 2 divisors, whose sum is σ = 1327251111492. Its totient is φ = 1327251111490.
The previous prime is 1327251111469. The next prime is 1327251111547. The reversal of 1327251111491 is 1941111527231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1327251111491 is a prime.
It is not a weakly prime, because it can be changed into another prime (1327251111451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 663625555745 + 663625555746.
It is an arithmetic number, because the mean of its divisors is an integer number (663625555746).
Almost surely, 21327251111491 is an apocalyptic number.
1327251111491 is a deficient number, since it is larger than the sum of its proper divisors (1).
1327251111491 is an equidigital number, since it uses as much as digits as its factorization.
1327251111491 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15120, while the sum is 38.
The spelling of 1327251111491 in words is "one trillion, three hundred twenty-seven billion, two hundred fifty-one million, one hundred eleven thousand, four hundred ninety-one".
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