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132737512502081 is a prime number
BaseRepresentation
bin11110001011100101011100…
…010001111111001101000001
3122101222120201110202002022202
4132023211130101333031001
5114344232411200031311
61150150434343242545
736646653205065404
oct3613453421771501
9571876643662282
10132737512502081
1139326732390743
1212a79504449455
13590b12ab95c86
1424ac75c005d3b
151052c19a58e3b
hex78b95c47f341

132737512502081 has 2 divisors, whose sum is σ = 132737512502082. Its totient is φ = 132737512502080.

The previous prime is 132737512502069. The next prime is 132737512502099. The reversal of 132737512502081 is 180205215737231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120664952257600 + 12072560244481 = 10984760^2 + 3474559^2 .

It is a cyclic number.

It is not a de Polignac number, because 132737512502081 - 210 = 132737512501057 is a prime.

It is a super-2 number, since 2×1327375125020812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132737512501081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66368756251040 + 66368756251041.

It is an arithmetic number, because the mean of its divisors is an integer number (66368756251041).

Almost surely, 2132737512502081 is an apocalyptic number.

It is an amenable number.

132737512502081 is a deficient number, since it is larger than the sum of its proper divisors (1).

132737512502081 is an equidigital number, since it uses as much as digits as its factorization.

132737512502081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 705600, while the sum is 47.

The spelling of 132737512502081 in words is "one hundred thirty-two trillion, seven hundred thirty-seven billion, five hundred twelve million, five hundred two thousand, eighty-one".