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132743445661753 is a prime number
BaseRepresentation
bin11110001011101010111101…
…111011001100100000111001
3122102000011000222000211022021
4132023222331323030200321
5114344332034042134003
61150153255211354441
736650253221110123
oct3613527573144071
9572004028024267
10132743445661753
11393291a7509393
1212a7a69b452a21
13590b86515b444
1424acb61db6213
151052e6588c2bd
hex78babdecc839

132743445661753 has 2 divisors, whose sum is σ = 132743445661754. Its totient is φ = 132743445661752.

The previous prime is 132743445661733. The next prime is 132743445661759. The reversal of 132743445661753 is 357166544347231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96277149416464 + 36466296245289 = 9812092^2 + 6038733^2 .

It is a cyclic number.

It is not a de Polignac number, because 132743445661753 - 25 = 132743445661721 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132743445661691 and 132743445661700.

It is not a weakly prime, because it can be changed into another prime (132743445661759) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66371722830876 + 66371722830877.

It is an arithmetic number, because the mean of its divisors is an integer number (66371722830877).

Almost surely, 2132743445661753 is an apocalyptic number.

It is an amenable number.

132743445661753 is a deficient number, since it is larger than the sum of its proper divisors (1).

132743445661753 is an equidigital number, since it uses as much as digits as its factorization.

132743445661753 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 152409600, while the sum is 61.

The spelling of 132743445661753 in words is "one hundred thirty-two trillion, seven hundred forty-three billion, four hundred forty-five million, six hundred sixty-one thousand, seven hundred fifty-three".