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132774752514893 is a prime number
BaseRepresentation
bin11110001100001000000111…
…111101010111001101001101
3122102010010211210101202011112
4132030020013331113031031
5114400340143120434033
61150215513530101405
736652442100011336
oct3614100775271515
9572103753352145
10132774752514893
1139340502400535
1212a84777b7a865
1359117b41ba908
1424b0491c0728d
151053b990abc48
hex78c207f5734d

132774752514893 has 2 divisors, whose sum is σ = 132774752514894. Its totient is φ = 132774752514892.

The previous prime is 132774752514821. The next prime is 132774752515021. The reversal of 132774752514893 is 398415257477231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 91927481245924 + 40847271268969 = 9587882^2 + 6391187^2 .

It is a cyclic number.

It is not a de Polignac number, because 132774752514893 - 28 = 132774752514637 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132774752514193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66387376257446 + 66387376257447.

It is an arithmetic number, because the mean of its divisors is an integer number (66387376257447).

Almost surely, 2132774752514893 is an apocalyptic number.

It is an amenable number.

132774752514893 is a deficient number, since it is larger than the sum of its proper divisors (1).

132774752514893 is an equidigital number, since it uses as much as digits as its factorization.

132774752514893 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 355622400, while the sum is 68.

The spelling of 132774752514893 in words is "one hundred thirty-two trillion, seven hundred seventy-four billion, seven hundred fifty-two million, five hundred fourteen thousand, eight hundred ninety-three".