Base | Representation |
---|---|
bin | 11000101111000111… |
… | …01001110000101011 |
3 | 1021021111220012021111 |
4 | 30113203221300223 |
5 | 204144202431242 |
6 | 10033435051151 |
7 | 650044122346 |
oct | 142743516053 |
9 | 37244805244 |
10 | 13280123947 |
11 | 56a5313752 |
12 | 26a75a0ab7 |
13 | 133843090c |
14 | 8dda4745d |
15 | 52ad36817 |
hex | 3178e9c2b |
13280123947 has 2 divisors, whose sum is σ = 13280123948. Its totient is φ = 13280123946.
The previous prime is 13280123933. The next prime is 13280123959. The reversal of 13280123947 is 74932108231.
It is a strong prime.
It is an emirp because it is prime and its reverse (74932108231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13280123947 - 215 = 13280091179 is a prime.
It is not a weakly prime, because it can be changed into another prime (13280123447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6640061973 + 6640061974.
It is an arithmetic number, because the mean of its divisors is an integer number (6640061974).
Almost surely, 213280123947 is an apocalyptic number.
13280123947 is a deficient number, since it is larger than the sum of its proper divisors (1).
13280123947 is an equidigital number, since it uses as much as digits as its factorization.
13280123947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 40.
The spelling of 13280123947 in words is "thirteen billion, two hundred eighty million, one hundred twenty-three thousand, nine hundred forty-seven".
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