13280123933 has 2 divisors, whose sum is σ = 13280123934. Its totient is φ = 13280123932.

The previous prime is 13280123911. The next prime is 13280123947. The reversal of 13280123933 is 33932108231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6886842169 + 6393281764 = 82987^2 + 79958^2 .

It is a cyclic number.

It is not a de Polignac number, because 13280123933 - 2¹⁰ = 13280122909 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13280123893 and 13280123902.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13280123993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6640061966 + 6640061967.

It is an arithmetic number, because the mean of its divisors is an integer number (6640061967).

Almost surely, 2^13280123933 is an apocalyptic number.

It is an amenable number.

13280123933 is a deficient number, since it is larger than the sum of its proper divisors (1).

13280123933 is an equidigital number, since it uses as much as digits as its factorization.

13280123933 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23328, while the sum is 35.

The spelling of 13280123933 in words is "thirteen billion, two hundred eighty million, one hundred twenty-three thousand, nine hundred thirty-three".