Base | Representation |
---|---|
bin | 11110001100100011111001… |
… | …111000101101000000111111 |
3 | 122102012222211121022010010101 |
4 | 132030203321320231000333 |
5 | 114401332240240333201 |
6 | 1150241325442021531 |
7 | 36654546216345034 |
oct | 3614437170550077 |
9 | 572188747263111 |
10 | 132804581183551 |
11 | 39352119962812 |
12 | 12a8a5016478a7 |
13 | 5914558c25704 |
14 | 24b1ac15b338b |
15 | 1054842b40d01 |
hex | 78c8f9e2d03f |
132804581183551 has 2 divisors, whose sum is σ = 132804581183552. Its totient is φ = 132804581183550.
The previous prime is 132804581183531. The next prime is 132804581183587. The reversal of 132804581183551 is 155381185408231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132804581183551 - 243 = 124008488161343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132804581183492 and 132804581183501.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132804581183531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66402290591775 + 66402290591776.
It is an arithmetic number, because the mean of its divisors is an integer number (66402290591776).
Almost surely, 2132804581183551 is an apocalyptic number.
132804581183551 is a deficient number, since it is larger than the sum of its proper divisors (1).
132804581183551 is an equidigital number, since it uses as much as digits as its factorization.
132804581183551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608000, while the sum is 55.
The spelling of 132804581183551 in words is "one hundred thirty-two trillion, eight hundred four billion, five hundred eighty-one million, one hundred eighty-three thousand, five hundred fifty-one".
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