Base | Representation |
---|---|
bin | 11000101111101100… |
… | …11000010110001101 |
3 | 1021021212010121201111 |
4 | 30113312120112031 |
5 | 204201432031412 |
6 | 10034132212021 |
7 | 650133630451 |
oct | 142766302615 |
9 | 37255117644 |
10 | 13285033357 |
11 | 56a8067212 |
12 | 26a916a011 |
13 | 133945c3ab |
14 | 900564661 |
15 | 52b4a62a7 |
hex | 317d9858d |
13285033357 has 2 divisors, whose sum is σ = 13285033358. Its totient is φ = 13285033356.
The previous prime is 13285033351. The next prime is 13285033361. The reversal of 13285033357 is 75333058231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13076837316 + 208196041 = 114354^2 + 14429^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13285033357 is a prime.
It is a super-2 number, since 2×132850333572 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13285033351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6642516678 + 6642516679.
It is an arithmetic number, because the mean of its divisors is an integer number (6642516679).
Almost surely, 213285033357 is an apocalyptic number.
It is an amenable number.
13285033357 is a deficient number, since it is larger than the sum of its proper divisors (1).
13285033357 is an equidigital number, since it uses as much as digits as its factorization.
13285033357 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 226800, while the sum is 40.
The spelling of 13285033357 in words is "thirteen billion, two hundred eighty-five million, thirty-three thousand, three hundred fifty-seven".
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