13294031 has 2 divisors, whose sum is σ = 13294032. Its totient is φ = 13294030.

The previous prime is 13294013. The next prime is 13294037. The reversal of 13294031 is 13049231.

Together with previous prime (13294013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13294031 is a prime.

It is a super-2 number, since 2×13294031² = 353462520457922, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13293988 and 13294006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13294037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6647015 + 6647016.

It is an arithmetic number, because the mean of its divisors is an integer number (6647016).

Almost surely, 2^13294031 is an apocalyptic number.

13294031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13294031 is an equidigital number, since it uses as much as digits as its factorization.

13294031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

The square root of 13294031 is about 3646.0980513420. The cubic root of 13294031 is about 236.8930006533.

The spelling of 13294031 in words is "thirteen million, two hundred ninety-four thousand, thirty-one".