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1330001301312 = 2635831030357
BaseRepresentation
bin10011010110101010010…
…000010100111101000000
311201010222002002110200000
4103112222100110331000
5133242320313120222
62454554423400000
7165042446350215
oct23265220247500
94633862073600
101330001301312
11473061074992
1219591a8b3000
1398559826938
144852dc51b0c
15248e2c099ac
hex135aa414f40

1330001301312 has 168 divisors, whose sum is σ = 4001036728416. Its totient is φ = 437991971328.

The previous prime is 1330001301301. The next prime is 1330001301319. The reversal of 1330001301312 is 2131031000331.

It is a happy number.

1330001301312 is a `hidden beast` number, since 1 + 330 + 0 + 0 + 1 + 301 + 31 + 2 = 666.

It is a super-2 number, since 2×13300013013122 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1330001301319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 775638 + ... + 1805994.

It is an arithmetic number, because the mean of its divisors is an integer number (23815694812).

Almost surely, 21330001301312 is an apocalyptic number.

1330001301312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1330001301312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2000518364208).

1330001301312 is an abundant number, since it is smaller than the sum of its proper divisors (2671035427104).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1330001301312 is an equidigital number, since it uses as much as digits as its factorization.

1330001301312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1030467 (or 1030445 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 18.

Adding to 1330001301312 its reverse (2131031000331), we get a palindrome (3461032301643).

The spelling of 1330001301312 in words is "one trillion, three hundred thirty billion, one million, three hundred one thousand, three hundred twelve".