Base | Representation |
---|---|
bin | 10011010110101010010… |
… | …110110110101001111111 |
3 | 11201010222012022101121002 |
4 | 103112222112312221333 |
5 | 133242321232342343 |
6 | 2454554524200515 |
7 | 165042500034254 |
oct | 23265226665177 |
9 | 4633865271532 |
10 | 1330003012223 |
11 | 473062033366 |
12 | 19591b39913b |
13 | 98559ca5602 |
14 | 4853017942b |
15 | 248e2e468b8 |
hex | 135aa5b6a7f |
1330003012223 has 2 divisors, whose sum is σ = 1330003012224. Its totient is φ = 1330003012222.
The previous prime is 1330003012199. The next prime is 1330003012231. The reversal of 1330003012223 is 3222103000331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1330003012223 - 216 = 1330002946687 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1330003012195 and 1330003012204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330003012243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665001506111 + 665001506112.
It is an arithmetic number, because the mean of its divisors is an integer number (665001506112).
Almost surely, 21330003012223 is an apocalyptic number.
1330003012223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330003012223 is an equidigital number, since it uses as much as digits as its factorization.
1330003012223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 1330003012223 its reverse (3222103000331), we get a palindrome (4552106012554).
The spelling of 1330003012223 in words is "one trillion, three hundred thirty billion, three million, twelve thousand, two hundred twenty-three".
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