Base | Representation |
---|---|
bin | 11110001111011010001100… |
… | …111100101100110000100111 |
3 | 122102220201002010012101002211 |
4 | 132033122030330230300213 |
5 | 114413034124413311101 |
6 | 1150511300543144251 |
7 | 40004645652045631 |
oct | 3617321474546047 |
9 | 572821063171084 |
10 | 133000322010151 |
11 | 394181355109a2 |
12 | 12b0042a8a5087 |
13 | 5929b51a1b22b |
14 | 24bb36db57a51 |
15 | 105999c1e7c51 |
hex | 78f68cf2cc27 |
133000322010151 has 2 divisors, whose sum is σ = 133000322010152. Its totient is φ = 133000322010150.
The previous prime is 133000322010091. The next prime is 133000322010191. The reversal of 133000322010151 is 151010223000331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133000322010151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133000322010191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500161005075 + 66500161005076.
It is an arithmetic number, because the mean of its divisors is an integer number (66500161005076).
Almost surely, 2133000322010151 is an apocalyptic number.
133000322010151 is a deficient number, since it is larger than the sum of its proper divisors (1).
133000322010151 is an equidigital number, since it uses as much as digits as its factorization.
133000322010151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 133000322010151 its reverse (151010223000331), we get a palindrome (284010545010482).
The spelling of 133000322010151 in words is "one hundred thirty-three trillion, three hundred twenty-two million, ten thousand, one hundred fifty-one".
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