1330004445593 has 2 divisors, whose sum is σ = 1330004445594. Its totient is φ = 1330004445592.

The previous prime is 1330004445503. The next prime is 1330004445631. The reversal of 1330004445593 is 3955444000331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 792521916169 + 537482529424 = 890237^2 + 733132^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330004445593 - 2¹⁰ = 1330004444569 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1330004445593.

It is not a weakly prime, because it can be changed into another prime (1330004445503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665002222796 + 665002222797.

It is an arithmetic number, because the mean of its divisors is an integer number (665002222797).

Almost surely, 2^{1330004445593} is an apocalyptic number.

It is an amenable number.

1330004445593 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330004445593 is an equidigital number, since it uses as much as digits as its factorization.

1330004445593 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 388800, while the sum is 41.

The spelling of 1330004445593 in words is "one trillion, three hundred thirty billion, four million, four hundred forty-five thousand, five hundred ninety-three".