Base | Representation |
---|---|
bin | 10011010110101010011… |
… | …100010100100100111111 |
3 | 11201010222022000012200112 |
4 | 103112222130110210333 |
5 | 133242322114224003 |
6 | 2454555015020235 |
7 | 165042515154026 |
oct | 23265234244477 |
9 | 4633868005615 |
10 | 1330004445503 |
11 | 473062922198 |
12 | 19591b96a67b |
13 | 9855a387ac6 |
14 | 4853042d8bd |
15 | 248e312b3d8 |
hex | 135aa71493f |
1330004445503 has 2 divisors, whose sum is σ = 1330004445504. Its totient is φ = 1330004445502.
The previous prime is 1330004445493. The next prime is 1330004445593. The reversal of 1330004445503 is 3055444000331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1330004445503 - 238 = 1055126538559 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1330004445503.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330004445593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665002222751 + 665002222752.
It is an arithmetic number, because the mean of its divisors is an integer number (665002222752).
Almost surely, 21330004445503 is an apocalyptic number.
1330004445503 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330004445503 is an equidigital number, since it uses as much as digits as its factorization.
1330004445503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 32.
Adding to 1330004445503 its reverse (3055444000331), we get a palindrome (4385448445834).
The spelling of 1330004445503 in words is "one trillion, three hundred thirty billion, four million, four hundred forty-five thousand, five hundred three".
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