Search a number
-
+
13300100012417 is a prime number
BaseRepresentation
bin1100000110001010101110…
…1111001001100110000001
31202002110212211121201021012
43001202223233021212001
53220402101100344132
644141552005210305
72541620606540321
oct301425357114601
952073784551235
1013300100012417
1142685a47a6889
1215a9794700995
1375626a43336a
1433da2a55d281
15180e759ee0b2
hexc18abbc9981

13300100012417 has 2 divisors, whose sum is σ = 13300100012418. Its totient is φ = 13300100012416.

The previous prime is 13300100012399. The next prime is 13300100012467. The reversal of 13300100012417 is 71421000100331.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9287646334096 + 4012453678321 = 3047564^2 + 2003111^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13300100012417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13300100012392 and 13300100012401.

It is not a weakly prime, because it can be changed into another prime (13300100012467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650050006208 + 6650050006209.

It is an arithmetic number, because the mean of its divisors is an integer number (6650050006209).

Almost surely, 213300100012417 is an apocalyptic number.

It is an amenable number.

13300100012417 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300100012417 is an equidigital number, since it uses as much as digits as its factorization.

13300100012417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 13300100012417 its reverse (71421000100331), we get a palindrome (84721100112748).

The spelling of 13300100012417 in words is "thirteen trillion, three hundred billion, one hundred million, twelve thousand, four hundred seventeen".