Base | Representation |
---|---|
bin | 11110001111011010110110… |
… | …001001011000100011001111 |
3 | 122102220202212021210111211201 |
4 | 132033122312021120203033 |
5 | 114413042033334413403 |
6 | 1150511453313530331 |
7 | 40005002044060615 |
oct | 3617326611304317 |
9 | 572822767714751 |
10 | 133001013201103 |
11 | 3941845a693993 |
12 | 12b005a22739a7 |
13 | 5929c31c94b68 |
14 | 24bb3d787b6b5 |
15 | 10599dcc2a21d |
hex | 78f6b62588cf |
133001013201103 has 2 divisors, whose sum is σ = 133001013201104. Its totient is φ = 133001013201102.
The previous prime is 133001013201073. The next prime is 133001013201107. The reversal of 133001013201103 is 301102310100331.
It is a strong prime.
It is an emirp because it is prime and its reverse (301102310100331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133001013201103 - 213 = 133001013192911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133001013201107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500506600551 + 66500506600552.
It is an arithmetic number, because the mean of its divisors is an integer number (66500506600552).
Almost surely, 2133001013201103 is an apocalyptic number.
133001013201103 is a deficient number, since it is larger than the sum of its proper divisors (1).
133001013201103 is an equidigital number, since it uses as much as digits as its factorization.
133001013201103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 133001013201103 its reverse (301102310100331), we get a palindrome (434103323301434).
The spelling of 133001013201103 in words is "one hundred thirty-three trillion, one billion, thirteen million, two hundred one thousand, one hundred three".
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