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13300122100981 is a prime number
BaseRepresentation
bin1100000110001010110100…
…0011011010010011110101
31202002110221101011221002011
43001202231003122103311
53220402122224212411
644141554114444221
72541621265355422
oct301425503322365
952073841157064
1013300122100981
1142686062132a1
1215a979bb93671
13756271b98311
1433da2d46cd49
15180e77913c21
hexc18ad0da4f5

13300122100981 has 2 divisors, whose sum is σ = 13300122100982. Its totient is φ = 13300122100980.

The previous prime is 13300122100931. The next prime is 13300122101027. The reversal of 13300122100981 is 18900122100331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11617565487025 + 1682556613956 = 3408455^2 + 1297134^2 .

It is an emirp because it is prime and its reverse (18900122100331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13300122100981 is a prime.

It is a super-2 number, since 2×133001221009812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13300122100921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650061050490 + 6650061050491.

It is an arithmetic number, because the mean of its divisors is an integer number (6650061050491).

Almost surely, 213300122100981 is an apocalyptic number.

It is an amenable number.

13300122100981 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300122100981 is an equidigital number, since it uses as much as digits as its factorization.

13300122100981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 31.

The spelling of 13300122100981 in words is "thirteen trillion, three hundred billion, one hundred twenty-two million, one hundred thousand, nine hundred eighty-one".