Base | Representation |
---|---|
bin | 1100000110001010110110… |
… | …0110001111010101111111 |
3 | 1202002110222000100210020211 |
4 | 3001202231212033111333 |
5 | 3220402132043343403 |
6 | 44141555042253251 |
7 | 2541621436103023 |
oct | 301425546172577 |
9 | 52073860323224 |
10 | 13300131231103 |
11 | 4268610389952 |
12 | 15a97a3057227 |
13 | 756273a43c62 |
14 | 33da30768383 |
15 | 180e7861906d |
hex | c18ad98f57f |
13300131231103 has 2 divisors, whose sum is σ = 13300131231104. Its totient is φ = 13300131231102.
The previous prime is 13300131231089. The next prime is 13300131231113. The reversal of 13300131231103 is 30113213100331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13300131231103 is a prime.
It is a super-2 number, since 2×133001312311032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13300131231113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650065615551 + 6650065615552.
It is an arithmetic number, because the mean of its divisors is an integer number (6650065615552).
Almost surely, 213300131231103 is an apocalyptic number.
13300131231103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300131231103 is an equidigital number, since it uses as much as digits as its factorization.
13300131231103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 13300131231103 its reverse (30113213100331), we get a palindrome (43413344331434).
The spelling of 13300131231103 in words is "thirteen trillion, three hundred billion, one hundred thirty-one million, two hundred thirty-one thousand, one hundred three".
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