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13300210111 is a prime number
BaseRepresentation
bin11000110001100000…
…10001100110111111
31021022220200200022111
430120300101212333
5204214323210421
610035433354451
7650406630526
oct143060214677
937286620274
1013300210111
115705692791
1226b2268a27
13133c644316
149025954bd
1552c9a2ee1
hex318c119bf

13300210111 has 2 divisors, whose sum is σ = 13300210112. Its totient is φ = 13300210110.

The previous prime is 13300210093. The next prime is 13300210141. The reversal of 13300210111 is 11101200331.

13300210111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13300210111 - 27 = 13300209983 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13300210091 and 13300210100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13300210141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650105055 + 6650105056.

It is an arithmetic number, because the mean of its divisors is an integer number (6650105056).

Almost surely, 213300210111 is an apocalyptic number.

13300210111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300210111 is an equidigital number, since it uses as much as digits as its factorization.

13300210111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 13300210111 its reverse (11101200331), we get a palindrome (24401410442).

The spelling of 13300210111 in words is "thirteen billion, three hundred million, two hundred ten thousand, one hundred eleven".