1330021212433 has 2 divisors, whose sum is σ = 1330021212434. Its totient is φ = 1330021212432.

The previous prime is 1330021212323. The next prime is 1330021212439. The reversal of 1330021212433 is 3342121200331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1099796858944 + 230224353489 = 1048712^2 + 479817^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330021212433 - 2⁹ = 1330021211921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1330021212398 and 1330021212407.

It is not a weakly prime, because it can be changed into another prime (1330021212439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665010606216 + 665010606217.

It is an arithmetic number, because the mean of its divisors is an integer number (665010606217).

Almost surely, 2^{1330021212433} is an apocalyptic number.

It is an amenable number.

1330021212433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330021212433 is an equidigital number, since it uses as much as digits as its factorization.

1330021212433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1330021212433 its reverse (3342121200331), we get a palindrome (4672142412764).

The spelling of 1330021212433 in words is "one trillion, three hundred thirty billion, twenty-one million, two hundred twelve thousand, four hundred thirty-three".