Base | Representation |
---|---|
bin | 11110001111011100110011… |
… | …110010011001000100011010 |
3 | 122102220222022012012000211011 |
4 | 132033130303302121010122 |
5 | 114413110343000300010 |
6 | 1150512442413324134 |
7 | 40005105220665565 |
oct | 3617346362310432 |
9 | 572828265160734 |
10 | 133003121103130 |
11 | 39419341529983 |
12 | 12b00a9019664a |
13 | 592a1a98bb675 |
14 | 24bb5577c34dc |
15 | 1059ab2d03a8a |
hex | 78f733c9911a |
133003121103130 has 32 divisors (see below), whose sum is σ = 239530175809920. Its totient is φ = 53173570497600.
The previous prime is 133003121103107. The next prime is 133003121103137. The reversal of 133003121103130 is 31301121300331.
It is a super-3 number, since 3×1330031211031303 (a number of 43 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (133003121103137) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 877734132 + ... + 877885648.
It is an arithmetic number, because the mean of its divisors is an integer number (7485317994060).
Almost surely, 2133003121103130 is an apocalyptic number.
133003121103130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133003121103130 is a deficient number, since it is larger than the sum of its proper divisors (106527054706790).
133003121103130 is a wasteful number, since it uses less digits than its factorization.
133003121103130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 196614.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 133003121103130 its reverse (31301121300331), we get a palindrome (164304242403461).
The spelling of 133003121103130 in words is "one hundred thirty-three trillion, three billion, one hundred twenty-one million, one hundred three thousand, one hundred thirty".
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