Base | Representation |
---|---|
bin | 11110001111011100111010… |
… | …111100101001110001100011 |
3 | 122102220222121120020021201101 |
4 | 132033130322330221301203 |
5 | 114413111114223433012 |
6 | 1150512502344215231 |
7 | 40005111210042121 |
oct | 3617347274516143 |
9 | 572828546207641 |
10 | 133003241233507 |
11 | 394193a331a687 |
12 | 12b00b0446a517 |
13 | 592a1c875ca28 |
14 | 24bb569734911 |
15 | 1059abd632d57 |
hex | 78f73af29c63 |
133003241233507 has 2 divisors, whose sum is σ = 133003241233508. Its totient is φ = 133003241233506.
The previous prime is 133003241233439. The next prime is 133003241233553. The reversal of 133003241233507 is 705332142300331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133003241233507 - 211 = 133003241231459 is a prime.
It is not a weakly prime, because it can be changed into another prime (133003241233307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66501620616753 + 66501620616754.
It is an arithmetic number, because the mean of its divisors is an integer number (66501620616754).
Almost surely, 2133003241233507 is an apocalyptic number.
133003241233507 is a deficient number, since it is larger than the sum of its proper divisors (1).
133003241233507 is an equidigital number, since it uses as much as digits as its factorization.
133003241233507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 37.
Adding to 133003241233507 its reverse (705332142300331), we get a palindrome (838335383533838).
The spelling of 133003241233507 in words is "one hundred thirty-three trillion, three billion, two hundred forty-one million, two hundred thirty-three thousand, five hundred seven".
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