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133003241233439 is a prime number
BaseRepresentation
bin11110001111011100111010…
…111100101001110000011111
3122102220222121120020021121212
4132033130322330221300133
5114413111114223432224
61150512502344215035
740005111210041663
oct3617347274516037
9572828546207555
10133003241233439
11394193a331a625
1212b00b0446a47b
13592a1c875c9a5
1424bb5697348a3
151059abd632d0e
hex78f73af29c1f

133003241233439 has 2 divisors, whose sum is σ = 133003241233440. Its totient is φ = 133003241233438.

The previous prime is 133003241233399. The next prime is 133003241233507. The reversal of 133003241233439 is 934332142300331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 133003241233439 - 28 = 133003241233183 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133003241233396 and 133003241233405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133003241283439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66501620616719 + 66501620616720.

It is an arithmetic number, because the mean of its divisors is an integer number (66501620616720).

Almost surely, 2133003241233439 is an apocalyptic number.

133003241233439 is a deficient number, since it is larger than the sum of its proper divisors (1).

133003241233439 is an equidigital number, since it uses as much as digits as its factorization.

133003241233439 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 419904, while the sum is 41.

The spelling of 133003241233439 in words is "one hundred thirty-three trillion, three billion, two hundred forty-one million, two hundred thirty-three thousand, four hundred thirty-nine".