Base | Representation |
---|---|
bin | 10011010110101100001… |
… | …001110000001011010011 |
3 | 11201011001021222122111101 |
4 | 103112230021300023103 |
5 | 133242401440212433 |
6 | 2455001521525231 |
7 | 165043314042604 |
oct | 23265411601323 |
9 | 4634037878441 |
10 | 1330033132243 |
11 | 473078035a42 |
12 | 1959294a3817 |
13 | 985632c00ca |
14 | 48534179dab |
15 | 248e58e607d |
hex | 135ac2702d3 |
1330033132243 has 2 divisors, whose sum is σ = 1330033132244. Its totient is φ = 1330033132242.
The previous prime is 1330033132237. The next prime is 1330033132249. The reversal of 1330033132243 is 3422313300331.
It is a balanced prime because it is at equal distance from previous prime (1330033132237) and next prime (1330033132249).
It is a cyclic number.
It is not a de Polignac number, because 1330033132243 - 213 = 1330033124051 is a prime.
It is a super-2 number, since 2×13300331322432 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1330033132249) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665016566121 + 665016566122.
It is an arithmetic number, because the mean of its divisors is an integer number (665016566122).
Almost surely, 21330033132243 is an apocalyptic number.
1330033132243 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330033132243 is an equidigital number, since it uses as much as digits as its factorization.
1330033132243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664, while the sum is 28.
Adding to 1330033132243 its reverse (3422313300331), we get a palindrome (4752346432574).
The spelling of 1330033132243 in words is "one trillion, three hundred thirty billion, thirty-three million, one hundred thirty-two thousand, two hundred forty-three".
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