Base | Representation |
---|---|
bin | 1100000110001011101000… |
… | …1110001111000001001000 |
3 | 1202002111111202220220100022 |
4 | 3001202322032033001020 |
5 | 3220403100304321440 |
6 | 44142032050200012 |
7 | 2541626620341611 |
oct | 301427216170110 |
9 | 52074452826308 |
10 | 13300343042120 |
11 | 42687099a9682 |
12 | 15a9841b83008 |
13 | 7562a88a5214 |
14 | 33da50942c08 |
15 | 180e8c007cb5 |
hex | c18ba38f048 |
13300343042120 has 64 divisors (see below), whose sum is σ = 31227429363840. Its totient is φ = 5088739392000.
The previous prime is 13300343042113. The next prime is 13300343042137. The reversal of 13300343042120 is 2124034300331.
It is a self number, because there is not a number n which added to its sum of digits gives 13300343042120.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 85262195 + ... + 85418045.
It is an arithmetic number, because the mean of its divisors is an integer number (487928583810).
Almost surely, 213300343042120 is an apocalyptic number.
13300343042120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13300343042120 is an abundant number, since it is smaller than the sum of its proper divisors (17927086321720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13300343042120 is a wasteful number, since it uses less digits than its factorization.
13300343042120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 248646 (or 248642 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 13300343042120 its reverse (2124034300331), we get a palindrome (15424377342451).
The spelling of 13300343042120 in words is "thirteen trillion, three hundred billion, three hundred forty-three million, forty-two thousand, one hundred twenty".
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