Base | Representation |
---|---|
bin | 1100000110001011110111… |
… | …0111100111100101000101 |
3 | 1202002111200001001011202001 |
4 | 3001202331313213211011 |
5 | 3220403211440103102 |
6 | 44142042113345301 |
7 | 2541631262352454 |
oct | 301427567474505 |
9 | 52074601034661 |
10 | 13300404222277 |
11 | 4268740496197 |
12 | 15a985a568231 |
13 | 7562b84763b3 |
14 | 33da58b0ab9b |
15 | 180e92590487 |
hex | c18bdde7945 |
13300404222277 has 2 divisors, whose sum is σ = 13300404222278. Its totient is φ = 13300404222276.
The previous prime is 13300404222263. The next prime is 13300404222289. The reversal of 13300404222277 is 77222240400331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11751190856001 + 1549213366276 = 3428001^2 + 1244674^2 .
It is a cyclic number.
It is not a de Polignac number, because 13300404222277 - 231 = 13298256738629 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13300404022277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650202111138 + 6650202111139.
It is an arithmetic number, because the mean of its divisors is an integer number (6650202111139).
Almost surely, 213300404222277 is an apocalyptic number.
It is an amenable number.
13300404222277 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300404222277 is an equidigital number, since it uses as much as digits as its factorization.
13300404222277 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112896, while the sum is 37.
The spelling of 13300404222277 in words is "thirteen trillion, three hundred billion, four hundred four million, two hundred twenty-two thousand, two hundred seventy-seven".
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