Base | Representation |
---|---|
bin | 111101111011110101… |
… | …1010101101000100101 |
3 | 110201022022011010211111 |
4 | 1323313223111220211 |
5 | 4134343103231122 |
6 | 141033520505021 |
7 | 12415654224124 |
oct | 1736753255045 |
9 | 421268133744 |
10 | 133004352037 |
11 | 514525422a7 |
12 | 2193aa7b171 |
13 | c708450c2b |
14 | 661a4c5abb |
15 | 36d69b6d77 |
hex | 1ef7ad5a25 |
133004352037 has 2 divisors, whose sum is σ = 133004352038. Its totient is φ = 133004352036.
The previous prime is 133004351981. The next prime is 133004352071. The reversal of 133004352037 is 730253400331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129509295876 + 3495056161 = 359874^2 + 59119^2 .
It is a cyclic number.
It is not a de Polignac number, because 133004352037 - 215 = 133004319269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133004352337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66502176018 + 66502176019.
It is an arithmetic number, because the mean of its divisors is an integer number (66502176019).
Almost surely, 2133004352037 is an apocalyptic number.
It is an amenable number.
133004352037 is a deficient number, since it is larger than the sum of its proper divisors (1).
133004352037 is an equidigital number, since it uses as much as digits as its factorization.
133004352037 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 22680, while the sum is 31.
Adding to 133004352037 its reverse (730253400331), we get a palindrome (863257752368).
The spelling of 133004352037 in words is "one hundred thirty-three billion, four million, three hundred fifty-two thousand, thirty-seven".
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