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133005011 is a prime number
BaseRepresentation
bin1111110110101…
…11111011010011
3100021021100120112
413323113323103
5233022130021
621110431535
73203344466
oct773277323
9307240515
10133005011
11690946a7
12386625ab
132172b4b9
14139432dd
15ba23d5b
hex7ed7ed3

133005011 has 2 divisors, whose sum is σ = 133005012. Its totient is φ = 133005010.

The previous prime is 133005007. The next prime is 133005013. The reversal of 133005011 is 110500331.

It is a strong prime.

It is an emirp because it is prime and its reverse (110500331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133005011 - 22 = 133005007 is a prime.

It is a super-2 number, since 2×1330050112 = 35380665902220242, which contains 22 as substring.

Together with 133005013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133005013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66502505 + 66502506.

It is an arithmetic number, because the mean of its divisors is an integer number (66502506).

Almost surely, 2133005011 is an apocalyptic number.

133005011 is a deficient number, since it is larger than the sum of its proper divisors (1).

133005011 is an equidigital number, since it uses as much as digits as its factorization.

133005011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45, while the sum is 14.

The square root of 133005011 is about 11532.7798470273. The cubic root of 133005011 is about 510.4532827695.

Adding to 133005011 its reverse (110500331), we get a palindrome (243505342).

The spelling of 133005011 in words is "one hundred thirty-three million, five thousand, eleven".