133005201144133 has 4 divisors (see below), whose sum is σ = 134052486192640. Its totient is φ = 131957916095628.

The previous prime is 133005201144107. The next prime is 133005201144149. The reversal of 133005201144133 is 331441102500331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133005201144133 - 2¹³ = 133005201135941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133005201144095 and 133005201144104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133005201148133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 523642524063 + ... + 523642524316.

It is an arithmetic number, because the mean of its divisors is an integer number (33513121548160).

Almost surely, 2^{133005201144133} is an apocalyptic number.

It is an amenable number.

133005201144133 is a deficient number, since it is larger than the sum of its proper divisors (1047285048507).

133005201144133 is a wasteful number, since it uses less digits than its factorization.

133005201144133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1047285048506.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 133005201144133 its reverse (331441102500331), we get a palindrome (464446303644464).

The spelling of 133005201144133 in words is "one hundred thirty-three trillion, five billion, two hundred one million, one hundred forty-four thousand, one hundred thirty-three".