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13300531404211 is a prime number
BaseRepresentation
bin1100000110001100010101…
…1100110001110110110011
31202002111222220100200120001
43001203011130301312303
53220403442014413321
644142102455330431
72541634365365332
oct301430534616663
952074886320501
1013300531404211
1142687a6262927
1215a9895080a17
1375630891628c
1433da6b975d19
15180e9d813c91
hexc18c5731db3

13300531404211 has 2 divisors, whose sum is σ = 13300531404212. Its totient is φ = 13300531404210.

The previous prime is 13300531404197. The next prime is 13300531404227. The reversal of 13300531404211 is 11240413500331.

13300531404211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (11240413500331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13300531404211 - 211 = 13300531402163 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13300531404211.

It is not a weakly prime, because it can be changed into another prime (13300531404011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650265702105 + 6650265702106.

It is an arithmetic number, because the mean of its divisors is an integer number (6650265702106).

Almost surely, 213300531404211 is an apocalyptic number.

13300531404211 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300531404211 is an equidigital number, since it uses as much as digits as its factorization.

13300531404211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 13300531404211 its reverse (11240413500331), we get a palindrome (24540944904542).

The spelling of 13300531404211 in words is "thirteen trillion, three hundred billion, five hundred thirty-one million, four hundred four thousand, two hundred eleven".