Base | Representation |
---|---|
bin | 1100000110001100010101… |
… | …1100110001110111000011 |
3 | 1202002111222220100200120122 |
4 | 3001203011130301313003 |
5 | 3220403442014413402 |
6 | 44142102455330455 |
7 | 2541634365365354 |
oct | 301430534616703 |
9 | 52074886320518 |
10 | 13300531404227 |
11 | 42687a6262941 |
12 | 15a9895080a2b |
13 | 7563089162a2 |
14 | 33da6b975d2b |
15 | 180e9d813ca2 |
hex | c18c5731dc3 |
13300531404227 has 2 divisors, whose sum is σ = 13300531404228. Its totient is φ = 13300531404226.
The previous prime is 13300531404211. The next prime is 13300531404299. The reversal of 13300531404227 is 72240413500331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13300531404227 - 24 = 13300531404211 is a prime.
It is not a weakly prime, because it can be changed into another prime (13300531494227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650265702113 + 6650265702114.
It is an arithmetic number, because the mean of its divisors is an integer number (6650265702114).
Almost surely, 213300531404227 is an apocalyptic number.
13300531404227 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300531404227 is an equidigital number, since it uses as much as digits as its factorization.
13300531404227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 35.
Adding to 13300531404227 its reverse (72240413500331), we get a palindrome (85540944904558).
The spelling of 13300531404227 in words is "thirteen trillion, three hundred billion, five hundred thirty-one million, four hundred four thousand, two hundred twenty-seven".
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