1330103230331 has 2 divisors, whose sum is σ = 1330103230332. Its totient is φ = 1330103230330.

The previous prime is 1330103230321. The next prime is 1330103230333. The reversal of 1330103230331 is 1330323010331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1330103230331 - 2¹⁰ = 1330103229307 is a prime.

It is a super-2 number, since 2×1330103230331² (a number of 25 digits) contains 22 as substring.

Together with 1330103230333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1330103230297 and 1330103230306.

It is not a weakly prime, because it can be changed into another prime (1330103230333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665051615165 + 665051615166.

It is an arithmetic number, because the mean of its divisors is an integer number (665051615166).

Almost surely, 2^{1330103230331} is an apocalyptic number.

1330103230331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330103230331 is an equidigital number, since it uses as much as digits as its factorization.

1330103230331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 1330103230331 its reverse (1330323010331), we get a palindrome (2660426240662).

The spelling of 1330103230331 in words is "one trillion, three hundred thirty billion, one hundred three million, two hundred thirty thousand, three hundred thirty-one".