133011000000000 has 600 divisors, whose sum is σ = 479880859063320. Its totient is φ = 35467200000000.

The previous prime is 133010999999993. The next prime is 133011000000061. The reversal of 133011000000000 is 110331.

It is a tau number, because it is divible by the number of its divisors (600).

It is a super-2 number, since 2×133011000000000² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 8999992611 + ... + 9000007389.

Almost surely, 2^{133011000000000} is an apocalyptic number.

133011000000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133011000000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (239940429531660).

133011000000000 is an abundant number, since it is smaller than the sum of its proper divisors (346869859063320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133011000000000 is an frugal number, since it uses more digits than its factorization.

133011000000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14848 (or 14789 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 9.

Adding to 133011000000000 its reverse (110331), we get a palindrome (133011000110331).

The spelling of 133011000000000 in words is "one hundred thirty-three trillion, eleven billion", and thus it is an aban number.