Base | Representation |
---|---|
bin | 10011010110110000101… |
… | …111011001101001111010 |
3 | 11201011020122211112120122 |
4 | 103112300233121221322 |
5 | 133243031142012310 |
6 | 2455013311453242 |
7 | 165045240251531 |
oct | 23266057315172 |
9 | 4634218745518 |
10 | 1330110110330 |
11 | 4731075327a1 |
12 | 19594b227222 |
13 | 98576232b81 |
14 | 48540497318 |
15 | 248ec54e555 |
hex | 135b0bd9a7a |
1330110110330 has 32 divisors (see below), whose sum is σ = 2399574260736. Its totient is φ = 530850415104.
The previous prime is 1330110110323. The next prime is 1330110110359. The reversal of 1330110110330 is 330110110331.
It is a junction number, because it is equal to n+sod(n) for n = 1330110110299 and 1330110110308.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10236227 + ... + 10365353.
It is an arithmetic number, because the mean of its divisors is an integer number (74986695648).
Almost surely, 21330110110330 is an apocalyptic number.
1330110110330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1330110110330 is a deficient number, since it is larger than the sum of its proper divisors (1069464150406).
1330110110330 is a wasteful number, since it uses less digits than its factorization.
1330110110330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 131438.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 1330110110330 its reverse (330110110331), we get a palindrome (1660220220661).
Subtracting from 1330110110330 its reverse (330110110331), we obtain a palindrome (999999999999).
The spelling of 1330110110330 in words is "one trillion, three hundred thirty billion, one hundred ten million, one hundred ten thousand, three hundred thirty".
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