Base | Representation |
---|---|
bin | 10011010110110000101… |
… | …111110010100011101101 |
3 | 11201011020200000201111112 |
4 | 103112300233302203231 |
5 | 133243031203243313 |
6 | 2455013314001405 |
7 | 165045241155110 |
oct | 23266057624355 |
9 | 4634220021445 |
10 | 1330110212333 |
11 | 4731075a23a1 |
12 | 19594b276265 |
13 | 9857626a426 |
14 | 485404c2577 |
15 | 248ec56e8a8 |
hex | 135b0bf28ed |
1330110212333 has 64 divisors (see below), whose sum is σ = 1614554726400. Its totient is φ = 1071918731520.
The previous prime is 1330110212317. The next prime is 1330110212399. The reversal of 1330110212333 is 3332120110331.
It is not a de Polignac number, because 1330110212333 - 24 = 1330110212317 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1330110212299 and 1330110212308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1330110212303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 395982308 + ... + 395985666.
It is an arithmetic number, because the mean of its divisors is an integer number (25227417600).
Almost surely, 21330110212333 is an apocalyptic number.
It is an amenable number.
1330110212333 is a deficient number, since it is larger than the sum of its proper divisors (284444514067).
1330110212333 is a wasteful number, since it uses less digits than its factorization.
1330110212333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3810.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 1330110212333 its reverse (3332120110331), we get a palindrome (4662230322664).
The spelling of 1330110212333 in words is "one trillion, three hundred thirty billion, one hundred ten million, two hundred twelve thousand, three hundred thirty-three".
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