Base | Representation |
---|---|
bin | 1100000110001110011110… |
… | …0110110000001111001111 |
3 | 1202002120110211122010212112 |
4 | 3001203213212300033033 |
5 | 3220411130214204432 |
6 | 44142235405454235 |
7 | 2541654524220335 |
oct | 301434746601717 |
9 | 52076424563775 |
10 | 13301104444367 |
11 | 4268a6a777433 |
12 | 15a9a14b7137b |
13 | 75639a5628ac |
14 | 33dac3b01b55 |
15 | 180ed3ca87b2 |
hex | c18e79b03cf |
13301104444367 has 2 divisors, whose sum is σ = 13301104444368. Its totient is φ = 13301104444366.
The previous prime is 13301104444361. The next prime is 13301104444409. The reversal of 13301104444367 is 76344440110331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13301104444367 - 214 = 13301104427983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13301104444361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650552222183 + 6650552222184.
It is an arithmetic number, because the mean of its divisors is an integer number (6650552222184).
Almost surely, 213301104444367 is an apocalyptic number.
13301104444367 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301104444367 is an equidigital number, since it uses as much as digits as its factorization.
13301104444367 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 290304, while the sum is 41.
Adding to 13301104444367 its reverse (76344440110331), we get a palindrome (89645544554698).
The spelling of 13301104444367 in words is "thirteen trillion, three hundred one billion, one hundred four million, four hundred forty-four thousand, three hundred sixty-seven".
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