Base | Representation |
---|---|
bin | 11110001111100100010000… |
… | …000001111001110010100100 |
3 | 122102221201221000211011002221 |
4 | 132033210100001321302210 |
5 | 114413223223421433012 |
6 | 1150520243315242124 |
7 | 40005510221024503 |
oct | 3617442001716244 |
9 | 572851830734087 |
10 | 133011111124132 |
11 | 39421771700a1a |
12 | 12b0253bba9344 |
13 | 592ab81049647 |
14 | 24bbab4a1083a |
15 | 1059dce4cc507 |
hex | 78f910079ca4 |
133011111124132 has 24 divisors (see below), whose sum is σ = 238478220028440. Its totient is φ = 64874905021440.
The previous prime is 133011111124103. The next prime is 133011111124147. The reversal of 133011111124132 is 231421111110331.
It can be written as a sum of positive squares in 4 ways, for example, as 21057232281856 + 111953878842276 = 4588816^2 + 10580826^2 .
It is a junction number, because it is equal to n+sod(n) for n = 133011111124097 and 133011111124106.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52277457 + ... + 54762712.
It is an arithmetic number, because the mean of its divisors is an integer number (9936592501185).
Almost surely, 2133011111124132 is an apocalyptic number.
It is an amenable number.
133011111124132 is a deficient number, since it is larger than the sum of its proper divisors (105467108904308).
133011111124132 is a wasteful number, since it uses less digits than its factorization.
133011111124132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 107047791 (or 107047789 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 133011111124132 its reverse (231421111110331), we get a palindrome (364432222234463).
The spelling of 133011111124132 in words is "one hundred thirty-three trillion, eleven billion, one hundred eleven million, one hundred twenty-four thousand, one hundred thirty-two".
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