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133011142004231 is a prime number
BaseRepresentation
bin11110001111100100010001…
…110111101100111000000111
3122102221202000011221000122022
4132033210101313230320013
5114413223304323113411
61150520250341153355
740005511044350111
oct3617442167547007
9572852004830568
10133011142004231
1139421788082667
1212b0254a3bb85b
13592ab8756c0aa
1424bbab8b6c3b1
151059dd207bedb
hex78f911dece07

133011142004231 has 2 divisors, whose sum is σ = 133011142004232. Its totient is φ = 133011142004230.

The previous prime is 133011142004159. The next prime is 133011142004281. The reversal of 133011142004231 is 132400241110331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133011142004231 is a prime.

It is a super-2 number, since 2×1330111420042312 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 133011142004231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133011142004281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66505571002115 + 66505571002116.

It is an arithmetic number, because the mean of its divisors is an integer number (66505571002116).

Almost surely, 2133011142004231 is an apocalyptic number.

133011142004231 is a deficient number, since it is larger than the sum of its proper divisors (1).

133011142004231 is an equidigital number, since it uses as much as digits as its factorization.

133011142004231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 133011142004231 its reverse (132400241110331), we get a palindrome (265411383114562).

The spelling of 133011142004231 in words is "one hundred thirty-three trillion, eleven billion, one hundred forty-two million, four thousand, two hundred thirty-one".