133011142012423 has 8 divisors (see below), whose sum is σ = 134343630326736. Its totient is φ = 131678958528000.

The previous prime is 133011142012393. The next prime is 133011142012451. The reversal of 133011142012423 is 324210241110331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133011142012423 - 2¹³ = 133011142004231 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133011142012391 and 133011142012400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133011142012523) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 75330361 + ... + 77075842.

It is an arithmetic number, because the mean of its divisors is an integer number (16792953790842).

Almost surely, 2^{133011142012423} is an apocalyptic number.

133011142012423 is a deficient number, since it is larger than the sum of its proper divisors (1332488314313).

133011142012423 is a wasteful number, since it uses less digits than its factorization.

133011142012423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 152414945.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 133011142012423 its reverse (324210241110331), we get a palindrome (457221383122754).

The spelling of 133011142012423 in words is "one hundred thirty-three trillion, eleven billion, one hundred forty-two million, twelve thousand, four hundred twenty-three".