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13301121144293 is a prime number
BaseRepresentation
bin1100000110001110100010…
…0110011101010111100101
31202002120112000001120212022
43001203220212131113211
53220411144003104133
644142241203432525
72541655116163223
oct301435046352745
952076460046768
1013301121144293
114268a79143324
1215a9a1a685745
137563a0b5bbc8
1433dac600bb13
15180ed54a6998
hexc18e899d5e5

13301121144293 has 2 divisors, whose sum is σ = 13301121144294. Its totient is φ = 13301121144292.

The previous prime is 13301121144257. The next prime is 13301121144301. The reversal of 13301121144293 is 39244112110331.

13301121144293 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12486880207684 + 814240936609 = 3533678^2 + 902353^2 .

It is a cyclic number.

It is not a de Polignac number, because 13301121144293 - 240 = 12201609516517 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13301121144893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650560572146 + 6650560572147.

It is an arithmetic number, because the mean of its divisors is an integer number (6650560572147).

Almost surely, 213301121144293 is an apocalyptic number.

It is an amenable number.

13301121144293 is a deficient number, since it is larger than the sum of its proper divisors (1).

13301121144293 is an equidigital number, since it uses as much as digits as its factorization.

13301121144293 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 13301121144293 in words is "thirteen trillion, three hundred one billion, one hundred twenty-one million, one hundred forty-four thousand, two hundred ninety-three".