Base | Representation |
---|---|
bin | 11110001111100100011100… |
… | …000111110101000110110101 |
3 | 122102221202110011120112112010 |
4 | 132033210130013311012311 |
5 | 114413224132341120110 |
6 | 1150520315403514433 |
7 | 40005515233336254 |
oct | 3617443407650665 |
9 | 572852404515463 |
10 | 133011314004405 |
11 | 39421866180971 |
12 | 12b02597b28a19 |
13 | 592abb40a1945 |
14 | 24bbad394279b |
15 | 1059de2205020 |
hex | 78f91c1f51b5 |
133011314004405 has 16 divisors (see below), whose sum is σ = 213279746891904. Its totient is φ = 70785485974080.
The previous prime is 133011314004403. The next prime is 133011314004409. The reversal of 133011314004405 is 504400413110331.
It is not a de Polignac number, because 133011314004405 - 21 = 133011314004403 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133011314004403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9617586289 + ... + 9617600118.
It is an arithmetic number, because the mean of its divisors is an integer number (13329984180744).
Almost surely, 2133011314004405 is an apocalyptic number.
133011314004405 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
133011314004405 is a deficient number, since it is larger than the sum of its proper divisors (80268432887499).
133011314004405 is a wasteful number, since it uses less digits than its factorization.
133011314004405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19235186876.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 133011314004405 its reverse (504400413110331), we get a palindrome (637411727114736).
The spelling of 133011314004405 in words is "one hundred thirty-three trillion, eleven billion, three hundred fourteen million, four thousand, four hundred five".
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