Base | Representation |
---|---|
bin | 1100000110001110100101… |
… | …0001001011100010011011 |
3 | 1202002120112210010120012221 |
4 | 3001203221101023202123 |
5 | 3220411204334442301 |
6 | 44142242243444511 |
7 | 2541655313315641 |
oct | 301435121134233 |
9 | 52076483116187 |
10 | 13301132343451 |
11 | 4268a844a2427 |
12 | 15a9a22386737 |
13 | 7563a3280524 |
14 | 33dac76c5191 |
15 | 180ed6469da1 |
hex | c18e944b89b |
13301132343451 has 2 divisors, whose sum is σ = 13301132343452. Its totient is φ = 13301132343450.
The previous prime is 13301132343397. The next prime is 13301132343467. The reversal of 13301132343451 is 15434323110331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13301132343451 - 223 = 13301123954843 is a prime.
It is not a weakly prime, because it can be changed into another prime (13301132343481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650566171725 + 6650566171726.
It is an arithmetic number, because the mean of its divisors is an integer number (6650566171726).
Almost surely, 213301132343451 is an apocalyptic number.
13301132343451 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301132343451 is an equidigital number, since it uses as much as digits as its factorization.
13301132343451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 34.
Adding to 13301132343451 its reverse (15434323110331), we get a palindrome (28735455453782).
The spelling of 13301132343451 in words is "thirteen trillion, three hundred one billion, one hundred thirty-two million, three hundred forty-three thousand, four hundred fifty-one".
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