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1330120241 is a prime number
BaseRepresentation
bin100111101001000…
…0000011000110001
310102200212002221122
41033102000120301
510211002321431
6335553032025
744650556402
oct11722003061
93380762848
101330120241
1162290002a
12311555615
131827528c8
14c89219a9
157bb8ea7b
hex4f480631

1330120241 has 2 divisors, whose sum is σ = 1330120242. Its totient is φ = 1330120240.

The previous prime is 1330120217. The next prime is 1330120243. The reversal of 1330120241 is 1420210331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1190526016 + 139594225 = 34504^2 + 11815^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1330120241 is a prime.

Together with 1330120243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1330120243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665060120 + 665060121.

It is an arithmetic number, because the mean of its divisors is an integer number (665060121).

Almost surely, 21330120241 is an apocalyptic number.

It is an amenable number.

1330120241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330120241 is an equidigital number, since it uses as much as digits as its factorization.

1330120241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1330120241 is about 36470.8135500156. The cubic root of 1330120241 is about 1099.7575887316.

Adding to 1330120241 its reverse (1420210331), we get a palindrome (2750330572).

The spelling of 1330120241 in words is "one billion, three hundred thirty million, one hundred twenty thousand, two hundred forty-one".