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13301220003947 is a prime number
BaseRepresentation
bin1100000110001110111001…
…1111100101000001101011
31202002120202220002011210222
43001203232133211001223
53220411344310111242
644142255054400255
72541660426365621
oct301435637450153
952076686064728
1013301220003947
114269019a26017
1215a9a4780008b
137563b8493645
1433dad51c3511
15180edded35d2
hexc18ee7e506b

13301220003947 has 2 divisors, whose sum is σ = 13301220003948. Its totient is φ = 13301220003946.

The previous prime is 13301220003941. The next prime is 13301220004021. The reversal of 13301220003947 is 74930002210331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13301220003947 - 210 = 13301220002923 is a prime.

It is a super-3 number, since 3×133012200039473 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13301220003941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650610001973 + 6650610001974.

It is an arithmetic number, because the mean of its divisors is an integer number (6650610001974).

Almost surely, 213301220003947 is an apocalyptic number.

13301220003947 is a deficient number, since it is larger than the sum of its proper divisors (1).

13301220003947 is an equidigital number, since it uses as much as digits as its factorization.

13301220003947 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27216, while the sum is 35.

The spelling of 13301220003947 in words is "thirteen trillion, three hundred one billion, two hundred twenty million, three thousand, nine hundred forty-seven".